The
following table shows the coefficients of the sine polynomials for
the appropriate multiple angle. The top of the table shows the powers,
which begin with n and decrease by two for each additional term, if
any. The formulae on the right are meant to clarify the table. The
number of each term is k=0, 1, 2...
k
0
1
2
3
4
5
Power
1
3
5
7
9
11
Formulae
n
0
0
.
.
.
.
.
sin (0x)=0
1
1
.
.
.
.
.
sin(1x)=sin x
2
2
.
.
.
.
.
3
3
-4
.
.
.
4
4
-8
.
.
.
5
5
-20
16
.
.
.
6
6
-32
32
.
.
7
7
-56
112
-64
.
.
8
8
-80
192
-128
.
9
9
-120
432
-576
256
.
10
10
-160
672
-1024
512
.
Observations
from the table
What follows are observations, not all of which are proved on this
page. At this stage, they are hypotheses (if we are thinking
scientically about the data in the table) or conjectures (if we are
thinking mathematically). [They are all provable, however]
The
patterns in the table are quite interesting. We note the following:
The first term coefficients are equal to n.
There appear to be two patterns, one for even n and one for odd n.
We can also note that
and
Actually, these formula were inferred, rather than observed, by picking out
the powers of sine from the Chebyshev Method.
With the sine (opposite that for the
cosine), the lowest power is always positive. The lowest power of sine
in the table is 1. The first term is either sine or sine·cosine.
The subsequent terms alternate in sign; for
instance, term 1 is always negative, term 2, always positive,
etc.
The powers are all odd.
When n is odd, the terms consist of sines only; when n is even, each term contains cos x multiplied by a power of sin x.
The
final term's coefficient is 2n-1.
The number of terms is ceiling [(n)/2] ,
for instance for n=5, the number of terms is ceiling ( (5)/2)=3
When n is odd, the coefficients for sin nx are ± the same numbers appearing for the cosine.
For instance:
Proof
Relationship Between Terms n is even
Let us refer to the polynomial representing sin nx as Tn, and the coefficient of each term, k as , where k is term 0, 1... The formula relate to n>1 and k>0. refers to the numbers in the table above, with n referring to the rows and k to the columns. In point 3 above, we inferred:
[4.1]
When n is even, all the terms contain one fact of cos x. So the n row
has a factor of cosx, the n-1 row is pure sines, and the n-2 row also
contains a cos x. We abbreviate cos x as c and sin x as s. We can write [4.2] [4.3] [4.4]
According to Chebyshev [cos nx=2·cos(n-1)x-cos(n-2)x]: [4.5]
So, using Equations 4.3 and 4.4: [4.6]
Combining powers of sine: [4.7]
Equating powers of sine for the general terms in Equation 4.2 and 4.7, we find our formula: [4.8] ■
Relationship between terms when n is odd
Using
the same letters as before, to represent our functions and
coefficients, we note that when n is odd, the terms are pure sines.
Therefore, we can write our functions as: [5.1] [5.2] [5.3] According to Chebyshev [cos nx=2·cos(n-1)x-cos(n-2)x]:
Multiplying Equation 5.2 by 2c, we get: [5.4] Because: [5.5]
We can substitute for cos2 x, c2, with Equation 5.5 in 5.4: [5.5]
Combining the coefficients of like powers: [5.6] To complete our work, we now need to subtract Equation 5.3 from 5.6, to complete our Chebyshev relationship.
[5.7]
Collecting like terms in Equation 5.7 [5.8]
By equating the general terms (same powers of sine) in Equation 5.1 and Equation 5.8, we obtain our equation: [5.9]
■
The first term coefficient is n
Whether n is odd or even, the first term (in Equations 4.7 and 5.8) is:
[6.1]
That is, in terms of the coefficients: [6.2]
Rearranging, [6.3]
Noting
that the difference between any two terms, (n>1), is a constant, and
writing this as "a", and taking another step of noting from the table
the difference between any two terms, we find: [6.4]
That is, [6.5]
When
n=1, then the first term coefficient is 1. As we increment n by 1, we
also increment the first term coefficient by 1 (according to Equation
6.5). Therefore the first term is equal to n.
In other words, when n=1, =1=n. When we increment n by 1, we also increment by 1 (by Equation 6.5), so remains equal to n for all n.
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